Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au
Last update: 16 March 2013
Geometry of Type
Let
Then we define the symplectic group
If we write
then the condition yields
and
Although it is not immediately obvious,
Let and
Each root space
in is 1-dimensional, and we choose distinguished vectors
in each one.
Let be the set of semisimple elements of and let
be the set of nilpotent elements of Then acts on the set
by
For let be a non-zero element in the
root space of Let
be the subgroup of diagonal matrices in Then
is a bijection satisfying
for Since
acts on and two diagonal elements and
are in the same if and only if they are in the same
The map is
giving a bijection
The weight satisfies
and
for
or 2, and Then define
for so that
for and
(We could have used
and
in our definitions or
but all that matters
is to have some elements of that satisfy 3.4.)
We begin by choosing a set of representatives for the orbits in for all
values of After this, we give the bijection between
and the irreducible
Theorem 3.19.
If is not a primitive root of
unity with then the following is a set of representatives of the orbits in
and
Proof.
Given an element
by 3.9, there is an element in the
of such that
is diagonal and that
for some such that
is in the set of representatives listed in (2.6). Then by Lemma 3.9, it is sufficient to
describe the in
for a set of representatives of possible central characters
Also, Theorem 3.6 shows that is spanned by
Case 1:
For the semisimples corresponding to
so that 0 is the only nilpotent that can be paired with Note that if
takes the form
then
so that these characters are in the same Hence only one pair
is listed, and it listed separately from the other pairs involving
or
Case 2:
For the weights
so that is 1-dimensional. Let
with Then
Then all the elements
with are to
or
Note that
are in the same orbit, so the is deleted from these semisimples in the listing above.
Case 3: for
If then
and is generated by and
for
Let
If then
so that
is to
If then
and if then
Then every element with
is conjugate to
or
Case 4:
If then
If then
Hence every pair with
is conjugate to one of these three elements of
but since
none of these three elements are conjugate to each other. Thus
and
are the representatives of the orbits of elements of with
Case 5:
If then
If then
Hence every pair with
is conjugate to one of these three elements of
Since
consists of exactly the diagonal
matrices, the of
is
Thus
and
are representatives of the orbits of elements of with
Since
are in the same orbit, the is deleted from the pairs involving this semisimple above.
Case 6:
If then
and
Let
with If
then
so we assume
If then
If then
But
Thus the elements in with
are represented by
and
Theorem 3.20.
If is a primitive 4th root of unity then the following is a set of representatives of the orbits in
and
Proof.
The proof of Theorem 3.19 applies to this case as well, with changes only necessary in Case 4 and for the semisimple
Since
is in the same
as
is in the same as
and thus
is omitted from the list. Also,
the two weights with
are in the same and thus the is omitted in the list of representatives.
Case 4:
If then
If then
is not nilpotent, since its minimal polynomial in the standard representation is
Then
Hence every pair with
is conjugate to one of these six elements of
but since
none of these elements are conjugate to each other. Thus the pairs
and
are representatives of the orbits of elements of with
However, later calculations are made easier by choosing nilpotent elements in as representatives. Then we note:
and
These are the representatives listed above.
Theorem 3.21.
If is a primitive third root of unity then the following is a set of representatives of the orbits in
Proof.
The proof of Theorem 3.19 applies, with changes only necessary in cases 3 and 4, and omitting the characters
and
(Case 4), since these characters are
in the same orbits as and
respectively.
Case 3: for
If then
is spanned by
and
while is generated by and
for
In particular,
contains
a representative of in
Let
which is nilpotent. Since
we assume that or 1.
If then case 3 in the proof of Theorem 3.19 shows that either
or is
to
Next assume
If
then
If then
and if then
Then every element
with is conjugate to
or
Later calculations are made easier if we choose representatives of in
So we note:
and
These are the representatives listed above.
Theorem 3.22.
If then the following is a set of representatives of the orbits in
and
Proof.
The proof of Theorem 3.19 applies to this case as well, with essential changes only necessary in Cases 2, 3 and 4 and for the semisimple
Case 1 now covers the central characters
and Since
is in the same
as
is in the same
as
and thus
(Case 4) is omitted from the list.
Case 2: for
or
Since
where is or
is spanned by
However,
is nilpotent
exactly when Since
and
every element of is
to either
or
Case 3: for
If then
is spanned by
and
And is generated by
and
for
In particular,
contains representatives of
and and thus of
as well.
Let
Then is nilpotent exactly if
since its minimal polynomial in the standard representation of is
By applying the argument in case 3 of Theorem 3.19, is
conjugate to an element of with its positive part equal to either
or 0. Thus we may assume
Then if is nilpotent,
as well.
If but
then
If but
then
which is in the same as
If exactly one of is non-zero, then
for some
But the roots and
are in the same orbit under the action of and
Hence,
is conjugate to where
is equal to the non-zero coefficient of
Finally,
Thus every element of is in the same
as either
or 0.
Case 4: for
If then
is spanned by
and
while is generated by and
By the argument in case 4 of theorem 3.19, if is in the span of
and
then is to either
or
We also note that
since is the same as in the generic case.
A similar argument using
in place of shows that if
is in the span of
and
then is
to either or
We now examine the general case. Let
Assume that not all of are zero and not all of
are zero, or else we are in one of the cases above. As noted above,
is to either
or
Let
or
for some
Then because the positive and negative parts of are fixed by the action of
or
Thus we can assume and
or
and
Case 1:
If
then the minimal polynomial of in the defining representation of
is
Hence if is
nilpotent, Then if
If then
Case 2:
If
then the minimal polynomial of in the defining representation of
is
Hence if is nilpotent, and either or is zero.
If then
Then
Thus, is in the orbit of either
or
Future computations will be easier if we choose orbit representatives with
Then we note:
and
These are the orbit representatives listed above.
Theorem 3.23.
If then the following is a set of representatives of the orbits in
and
Proof.
By (3.9) and the classification of central characters given in 2.4.1, the semisimple elements listed above are a set of representatives of the semisimple orbits in
Then it suffices to show that the nilpotent elements paired with each
are a set of representatives of the
in
For
The centralizer of in is generated by
and
Case 1:
Since is central,
and
Hence the nilpotent
in
are the nilpotent orbits in These are
represented by 0,
and
Case 2: and
If or
then
where or 2, respectively. In these cases,
is generated by and
for In particular,
contains a representative of
However,
is nilpotent exactly if If
then
so we assume that
Then
so that every non-zero element of is
to
Case 3:
If then
and is spanned by
and Also,
is generated by and
and
for In particular,
contains a representative of
and
However,
is nilpotent exactly if and However,
and
so we can assume
Then if
If but
then
if but then
Hence is in the
of either 0, or
Case 4:
If then
and
Cosets
The irreducible can also be constructed as the Borel-Moore homology of
generalized Springer fibers. If is a semisimple element of and
then
is the set of Borel subalgebras fixed by
and containing Identifying
with shows that is the set of
in fixed by the action of and
Thus, it is necessary to compute this action of
on cosets in
The group is generated by:
with some added relations (see [Ste1967]).
The first relations are commutator relations between the
The next relations describe how the Weyl group interacts with the
Explicitly, is generated by
The Varieties
We use Theorem 3.8 to determine the varieties for semisimple elements
The following semisimple elements are defined only up to an element of
but this does not affect
First,
so that
Next,
Then consists of
and
for
If then
Then consists of
and
for Geometrically, this consists of four disjoint copies of
Next,
Then contains
and
for (This changes for specific values of only if
in which case
is central.) Geometrically,
this consists of four disjoint copies of
Next,
Then contains
and
for (This changes only if
in which case
was computed above.) Geometrically, this consists of four disjoint copies of
Next,
Then consists of
and
for (This changes only if
in which case
was computed above.) Geometrically, this consists of four disjoint copies of
Next,
Then contains
and
for (This changes only if
in which case was computed above.)
Geometrically, this is four disjoint copies of
If
then
Then contains
and
for Geometrically, this is four disjoint copies of
Next,
Then
consists of for
eight disjoint points.
This changes if
or
If
then is central.
If then
is in the same orbit as above. If
then
consists of for
and
Geometrically, this is four disjoint copies of
If
then
Then
consists of for which
is eight disjoint points.
Next,
Then
consists of for which
is eight disjoint points.
If
then
Then
consists of for which
is eight disjoint points.
Nilpotent Elements
The next goal is to understand the action of
on the elements of
Case:
Cosets starting with
Cosets starting with
Case:
Cosets starting with
Cosets starting with
Case:
Cosets starting with
Cosets starting with
Case:
Cosets starting with
Cosets starting with
Cosets starting with
Cosets starting with
Case:
Cosets starting with
Cosets starting with
The varieties
We examine the varieties which are
the cosets in fixed by both and
for each pair
listed in Theorems 3.19-3.23. The Kazhdan-Lusztig classification calls for an examination of the action of the simultaneous centralizer in of
and on
Note that is always contained in this
centralizer, but acts trivially on Thus in the
discussion below, we let be the quotient of the centralizer of
and by the center.
Generic
If then
so we only specify if
When the homology
is the principal series module
If
then consists of
and
This is a single and two points. The centralizer of is generated by
and
so that is generated by
and
and is trivial.
If
then consists of
and
This is a single and two points. The centralizer of is generated by
and
so that is generated by
and
Then
We examine how acts on
This is a homeomorphism on and switches the two points.
be generated by β, and
which are the generators of
and of the points
and
respectively. Then the component
is 1-dimensional, generated by where
is the non-trivial representation of
is 3-dimensional, generated by and
where triv is the
trivial representation of
If
then consists of
and
which is one copy of and two points. The centralizer of is generated by
and
so that is generated by
and
and is trivial.
If
then consists of
and
which is two disjoint copies of The centralizer of is generated by
and
so that is generated by
and
and is trivial.
If
then consists of
and
which is two disjoint copies of The centralizer of is generated by
and
so that is generated by
and
and is trivial.
If
then consists of four points -
and
The centralizer of is so that
and is trivial.
If
then consists of four points -
and
The centralizer of is so that
and is trivial.
If
then
The centralizer of is so that
and is trivial.
If
then consists of four points -
and
The centralizer of is so that
and its component group is trivial.
If
then consists of four points -
and
The centralizer of is so that
and is trivial.
If
then consists of two points -
and The centralizer of
is so that
However,
acts trivially on so
For
if
then consists of four points -
and
The centralizer of is so that
and is trivial.
For
if
then consists of four points -
and
The centralizer of is so that
and is trivial.
The varieties from the previous section change for the orbit of the semisimple element
which now includes
In this case contains 6 non-zero orbits, 3 of which are not present for generic
Note that
If
then
Then consists of four points -
and
The centralizer
of is so that
is
and is trivial.
Next,
If
then consists of and
The centralizer of is
so that
and is
However,
acts trivially on
so that
Finally,
If
then
Then consists of The
centralizer of is so that
is trivial.
The varieties change from the generic case for in the orbit of
which is now in the same orbit as
depending on whether is 1 or The
in are
represented by
and
If
then consists of
and
which is one copy of
and two points. The centralizer of is generated by
and
so that
is generated by
and
Then is trivial.
Note that
If
then consists of
and
which is two copies of
The centralizer of is generated by
and
so that
is generated by
for
and
Then is trivial.
Finally,
If
then consists of only The
centralizer of is generated by
and so that
is generated by
for and
Hence is trivial.
Again, we note only the changes from the generic case. Also note that
If
then the in
are represented by
and
We can check which nilpotent elements satisfy condition 3.1 using the following procedure. First, we note that an element of
takes the form
Then for each we find an
By computing the commutator
we can determine necessary and sufficient conditions for
to commute with We then check, using the standard representation of
whether an element satisfying those conditions is necessarily nilpotent. We outline this check below.
Specifically,
commutes with and
commutes with
so that and
are not considered.
If
then consists of
and
a
and two points. The centralizer of is generated by and
so that is generated by
and
Then
If
then consists of
and
a
and two points. The centralizer of is generated by and
so that is generated by
and Then
In both of these cases, as in the case of generic the action of
on
switches the points
and
and is a homeomorphism on
Thus the component of
corresponding to the sign representation is 1-dimensional, spanned by
while the component corresponding to the trivial representation is 3-dimensional.
If
then The centralizer of
is generated by and
so that is trivial.
If
then
The centralizer of is generated by and
so that
is trivial.
Thus, the triples
and
must correspond to the 1-dimensional modules with weights and
respectively, since
the homology of those varieties are each 1-dimensional. Then
and
correspond to the 2-dimensional modules, which have weights and
However, this leaves us with two triples not yet assigned to a module,
and
and every module has been accounted for. This is the first case where Grojnowski’s condition 3.2 seems to be missing some information about the representation
in the triple
In particular, eliminating the triples
and
from our indexing set makes the correspondence a bijection.
If
then consists of
and
two disjoint copies of The centralizer of is generated by
and
so that
is generated by
and
Then is trivial.
If
then consists of
and
two disjoint copies of The centralizer of is generated by
and
so that is generated by
and
The group
is isomorphic to
generated by
but this
group acts trivially on
If
then consists of
and
two disjoint copies of The centralizer of is generated by
and
so that
is generated by
and
The group
is isomorphic to
generated by
but this group
acts trivially on
If
and
then consists of four points -
and
The centralizer
of is so that is
Then is trivial.
If
and
then consists of four points -
and
The centralizer
of is so that is
Then is trivial.
If
and
then consists of four points -
and
The centralizer
of is so that is
Then is trivial.
If
and
then consists of four points -
and
The centralizer
of is so that is
Then is trivial.
When
for any
and is the
Lie group generated by and
In fact, if and are elements of
then
as well. Then is a Lie subalgebra of and
is its associated Lie Group. Then the
orbits of
are exactly the (adjoint) nilpotent orbits of
In addition, the set of Borel subgroups of
is precisely
and the Weyl group of
is
the stabilizer of in
Then, the Springer correspondence gives a bijection between irreducible representations of and
of pairs
where is a nilpotent element of
and is a simple representation of the component group of
that appears in
But these
are exactly the of triples
where is a simple
representation of that appears in
Then the orbits of such triples are in bijection with the irreducible representations of In
turn, the results of section 1.2.9 show that the irreducible representations of are in bijection with the irreducible
representations of with central character Thus, if
using the Springer correspondences for all the potential groups
gives a geometric indexing of the irreducible representations of
Bijections
We summarize the bijections between irreducible representations of and orbits in
paired with representations of
appearing in
Generic
Note that
is omitted from this bijection since
is not contained in and thus condition 3.1 omits it.
For the central character t1,q2 when
q4=1, we note that condition 3.1 omits the nilpotent
CG(st)-orbits of 0,
e±α2, and
eα2+e-2α1-α2 from conisderation.
q2=1
Central CharacterDimensionIndexingWeightst1,11(st,0,1)signt1,12(st,eα1,1)t1,11(st,eα1,-1)t1,11(st,eα2,1)t1,11(st,eα1+eα2,1)trivt1,z4(st,0,1)sign⊗H∼{1}H∼t1,z4(st,eα1,1)triv⊗H∼{1}H∼tq,14(st,0,1)sign⊗H∼{1}H∼tq,14(st,e2α1+α2,1)triv⊗H∼{1}H∼tz,14(st,0,1)sign⊗H∼{1}H∼tz,14(st,eα2,1)triv⊗H∼{1}H∼tz,w8(st,0,1)triv⊗ℂ[X]H∼Table 31: Geometric Indexing in TypeC2, withq=-1.
Notes and References
This is an excerpt from Matt Davis' Ph.D Thesis entitled Representations of Rank Two Affine Hecke Algebras at Roots of Unity, University of Wisconsin, 2010.