Weight lattices

Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au

Last update: 19 September 2012

GLn()

T= { ( x1 0 0 xn ) xi × }

Define

Xεi: T× byXεi ( x1 0 0 xn ) =Xi, hεi: ×T byhεi (t)= ( ( 1 0 1 t 1 0 1 ) ) .

Then

𝔥* = { (Xε1)λ1 (Xεn)λn λ1,, λn } 𝔥 = { (hε1)λ1 (hε1)λn λ1,, λn } N(T) = { n×nmatrices with exactly one nonzero entry on each row and each column } W0 = N(T)T= {wTwSn} where Sn = {permutation matrices}.

SLn()

T= { ( x1 0 0 xn ) x1xn=1 }

With Xεi:T× and hεi:×TGLn as in ???

𝔥* = Xε1,, Xεn Xε1Xεn =1 𝔥 = hε1-ε2 ,, hεn-1-εn = { h λ1ε1 ++ λnεn λ1++λn=0 } N(T) = { n×nmatrices with (a) exactly one nonzero entry in each row and each column (b) product of the nonzero entries is 1

PGLn()

T= { [ x1 0 0 xn ] [ x1 0 0 xn ] = [ λx1 0 0 λxn ] forλ× }

Then with Xεi: TGLn× and hεi: ×TGLn TPGL

𝔥* = { xλ= x λ1ε1++ λnεn λi ,λ1++ λn=0 } 𝔥 = hε1 ,, hεn hε1 ,, hεn =1 .

For SL2

𝔥* ε2 ε1

Identify points on diagonal lines.

The 2-fold cover of –span{ε1-ε2} is very visible.

𝔥 ε2 ε1 𝔥=–span {ε1-ε2} .

SL3

ε2+ε3 ε1+ε3 ε1+ε2 ε1+ε2+ε3 ε2 ε3 ε1

The weight lattice of SL3 as a 3–fold cover of

span { ε1-ε2, ε2-ε3 } = { λ1ε1+ λ2ε2+ λ3ε3 λ1+λ2+ λ3=0 } .

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