Quantum groups and Lyndon words

Data for quiver Hecke algebras

Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au
and

Department of Mathematics
University of Wisconsin, Madison
Madison, WI 53706 USA
ram@math.wisc.edu

Last updates: 10 April 2010

Quantum groups and Lyndon words

In these three talks, I will explore the connections between

  1. Mirkovic-Vilonen polytopes,
  2. the Littelmann path model,
  3. quantum groups,
  4. free Lie algebras,
  5. words.

The lectures will proceed as follows:

  1. Combinatorics
  2. Algebra
  3. Geometry

Let be an alphabet, and let * ={words on  }.

Let 𝒫 be the free associative algebra generated by a set of elements pi, indexed by the elements i.

is generated by pi,i,  and with a bracket operation []:× . There are many possible bracket operations:

  1. [u,v]=uv-vu.
  2. [u,v]=uv- q deg(u) deg(v) vu.

Example: Consider the alphabet ={+,-}. A typical word will be ++-+-- . A typical element of 𝒫 will be p+ p- -2 p- p+ 𝒫. If the bracket is [u,v]=uv-vu, then [ p+ , p- ]= p+ p- - p- p+ , and [ p+ , p- ]=-[ p- , p+ ]

𝒫 is the enveloping algebra of . Choose a total order on and then use the lexicographic order on * . L= l * | l l 2   if  l= l 1 l 2 is the set of Lyndon words. For lL define l = l 1 l 2 ,if  l= l 1 l 2   with   l 1 L  of maximum length  l,  and   k =l  if  lI.

Example: (cont) There are two possible choices for the ordering: +<- or -<+. If +<- then +-L but -+L. Then + = p + , - = p - and +- = - + = p - p +

  1. If u I * then u has a unique factorisation u= l 1 l 2 l n with l 1 ,, l n L, l 1 l n .
  2. has basis l | lL and 𝒫 has basis l 1 l n | l 1 ,, l n L, l 1 l n .

The quantum group U -

𝒫 is graded by Q + = iI 0 αi with  deg p i 1 ,, p i l = α i 1 ++ α i l .
Example:

  1. (Type A 2 ) = +- . Then αi αj = 2 -1 -1 2
  2. (Type B n ) = 12n , then αi αj = 2 -2 0 -2 4 -2 -2 4 -2 0 -2 4

Fix a symmetric bilinear form , : Q + × Q + given by values , α i αj .

The dual of 𝒫 is =free algebra generated by   f i ,iI with p i f j = δ ij ,if   p i = p i 1 p i k   and   f j = f j 1 f j l . The , -shuffle product on is u·v= σ S k+l / S k × S l q wt σuv σ uv ,where  k=l u ,l=l v , the sum is over shuffles of u with v, wt σuv = 1i<jk+l,σ i >σ j - u i v k-j where u i is the i th letter in u and v k-j is the k-j th letter in v.

U - i the · -subalgebra of generated by f i ,iI.

Good Lyndon words

U - f i f i and 𝒫 U - p i f i and the restriction of , :𝒫× to U - , , : U - × U - is nondegenerate.

Example (cont) HW: Show that f + f + f + - q+ q -1 f + f - f + + f - f + f + =0 in U - .

The good words and the good Lyndon words are GL=GL and G= g I * | g  is the maximal word in an element of   U -

HW: f + f + f - = f + f + f - +q f - f + = f + f + f - + q -2 f + f + f - The shuffles f + f + f - and f + f - f + and f - f + f + are not independent and we must choose preferred words for a basis of U - . f + f - = f + f - +q f - f + so f - f + G.

Problem: Describe G for 2 -2 -2 2 .

(Lalonde-Ram, Leclerc)

  1. Assume that α i α j with α i = 2 αi αi αi is a symmetrisable Cartan matrix. Let + be the positive roots of the corresponding Kac-Mody Lie algebra 𝔤. GL + l deg l is a bijection with inverse + GL β l β given by l β =max l β 1 l β2 | β1 , β2 + , β1 + β2 β,l β1 <l β2
  2. PBW basis and canonical basis of U -
    U - has basis E g | gG , where E g = l 1 l 2 l k ifg= l 1 l k   with   l 1 ,, l k L  and   l 1 l k .
  3. The ordering on + induced by lexicographic ordering on GL determines a reduced ecomposition of w 0 , w 0 = s i 1 s i N ,so that + = β1 < βN with β1 = α i 1 , β2 = s i 1 α i 2 ,, βN = s i N α i N . Let -: U - U - be the automorphism given by f i - = f i and q - = q -1 . The canonical basis of U - is b g | gG given by b g - = b g and b g = E g + hG,h>g c gh E h , with c gh q q .

HW: If +<- then GL= +- +- and + = α+ α- - α+ + α-

Dual PBW and dual canonical bases

The dual PBW basis of U - is E g * | gG given by E g E h * = δ gh .

  1. (Lusztig) E h * = const E h .
  2. (Leclerc) b g * | gG is characterised by b g * = E g * + hG ,hg d gh E h * ,with   d gh q q , and b g * = h I * a gh h,with   a gh q+ q -1 . U - has bases PBW basis:: E g | g G , dual PBW basis:: E g * | g G , canonical basis:: b g | g G , dual canonical basis:: b g * | g G .

References [PLACEHOLDER]

[BG] A. Braverman and D. Gaitsgory, Crystals via the affine Grassmanian, Duke Math. J. 107 no. 3, (2001), 561-575; arXiv:math/9909077v2, MR1828302 (2002e:20083)

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