Arun Ram
Department of Mathematics and Statistics
University of Melbourne
Parkville, VIC 3010 Australia
aram@unimelb.edu.au
Last update: 2 December 2013
Reflection groups
Let be a finite dimensional vector space over The algebra
is the symmetric algebra of It can be identified with the algebra of
polynomial functions on the dual vector space
As a vector space,
An element is homogeneous of degree
if
The general linear group is the group
of all invertible linear transformations of A subgroup of
acts on
by
The invariant ring of is
A reflection
is an element of such that
i.e. is diagonalizable and has exactly one eigenvalue not equal to 1.
The reflection is the reflection in the hyperplane
A reflection group is a finite subgroup of
generated by reflections,
where is some index set for the reflections in
Let be a finite dimensional complex vector space and let be a finite subgroup of
Then
is a reflection group if and only if there are homogeneous elements
such that
is a ring isomorphism.
The theorem says that is a reflection group if and only if
is generated by algebraically independent homogeneous polynomials
Let be a finite subgroup of and let
by a bilinear form on Then the bilinear form
given by
is i.e.
Thus is a subgroup of the unitary group
The radical of the form is
The form is nondegenerate, if
The dual
of the vector space has a given by
and the map
is a homomorphism if and only if the form
is nondegenerate. If is a simple then we say that
acts irreducibly on If
is nondegenerate and acts irreducibly on then, by Schur’s lemma, the isomorphism in (???)
is unique up to constant multiples and so is, up to constant
multiples the unique nondegenerate bilinear form on
If is a reflection in the hyperplane
then, for any
If such that
then, for all
Let be a finite reflection group and let be a
in Let
The set is the root system of the pair
It is a set of vectors in which satisfy:
(1)
If, for each
is the reflection in the hyperplane
then
(2)
The root lattice
is contained in the weight lattice
(3)
is i.e. if and
then
Let
The chambers and the alcoves are the connected components of
respectively, where and
are the hyperplanes
Then
(a)
the reflection
in the hyperplane is given by
(b)
The reflection
in
in is given by
(c)
for the translation
in is given by
For and
The Weyl group the affine Weyl group, and the extended affine Weyl group are, respectively,
since, by the second relation in (???)
Fix a choice of a chamber in
The set of positive roots is
There are bijections
For the inversion set and the length of are
Let
be the walls of The corresponding elements of
and the corresponding reflections
are the
respectively. The fundamental weights
Then
Let be the unique alcove contained in whose closure contains
The element such that is a wall of
is the highest root of Then
is a bijection. The walls of are
and
and the reflection in is
For the inversion set and the length of are given by
If and then
Define
If then
and so
induces a permutation (also denoted by of the walls
of Then
Thus corresponds to automorphisms of the Dynkin diagram.
The basic data
A reflection in is an element
such that
A finite real reflection group is a finite subgroup of
which is generated by reflections. Any nondegenerate symmetric bilinear form
can be symmetrized to produce a form
given by
which is
Let be an index set for the reflections in Each reflection
in fixes a hyperplane
For any fixed choice of with
(i.e. for all
the reflection
is given by
since the linear transformation defined by the right hand side of the formula acts as the identity on
and takes to The hyperplanes
cut the whole space into a collection of cones, each of which is a fundamental chamber for the action of
The basic data is
a finite real reflection group,
a fixed fundamental chamber for
a lattice.
For each reflecting hyperplane fix
so that
is minimal such that
For let
with the positive side of being the side towards the chamber so that
For each reflection in let
be such that
is on the positive side of and and
is minimal. These are the positive roots
Let
Let
The raising operators are
and the dominance order is the partial order on given by
The dominance order on is the partial order defined by
This partial order on is often called the Bruhat order or the Bruhat-Chevalley order.
A fundamental theorem is the following theorem of Chevalley.
The data is equivalent to a different data
where
is a connected reductive algebraic group over
is a Borel subgroup of and
is a maximal torus of
These data are equivalent in the sense that each can be uniquely reconstructed from the other.
Example. The basic data corresponding to the group
Let be an orthonormal basis of
and
Symmetric functions
The group algebra of is
for all Define
Define
The elements satisfy
(a)
(b)
if
(c)
(d)
is divisible by
The orbit sums
form bases of and
respectively. The Weyl characters are
the inverse images of the elements of our favorite basis
of under the vector space isomorphism
(a vector space generalization of the bijection in (???)). Thus the
are a basis of
Let
Then
Proof.
For define
by
Then
Proof.
By (???) the coefficients defined by
where
If and
define
Let and let
Then
where
for an integer
Proof.
For part (b)
is a free
with basis
Proof.
For each define
????is this formula for correct???? and for each
define
The operators and satisfy the following relations
Proof.
For the second relation:
and if
So
The affine Hecke algebra
Fix The affine Hecke algebra
is the algebra over given by generators
and
and relations
The affine Hecke algebra is the algebra given by generators
and relations
The conversion between the two presentations is given by
The algebra has bases
Let
For each define
Let be the center of
Then
where the first map is a ring isomorphism and the second is a vector space isomorphism.
and the corresponding bases of are
Proof.
(a) First show that
Assume
Let be maximal in Bruhat order subject to
for some If there exists a dominant
such that
(otherwise
for every dominant which is impossible since is a finite linear
combination of Since
we have
Repeated use of the relation (4.11) yields
where are constants such that
for
and
unless
So
and comparing the coefficients of gives
Since
it follows that which is a contradiction.
Hence
The relation (4.11) gives
where
Comparing coefficients of on both sides yields
Hence
and therefore for
So
(b) Since
is in the center of the tiny little affine Hecke algebra generated by and the
Thus it follows that
and so
Thus
is a basis of Since
and
Since
is a basis of and
is a basis of
the composite map
is a vector space isomorphism.
(c) Now show that
First we can do a rank 1 calculation:
Now can be written as a linear combination of products of
and so
can be written as a linear combination of terms of the form
Thus
and the are some linear combinations of products of terms of the form
for roots By the Satake isomorphism we know that in fact
must be a symmetric function and so
where denotes the longest element. It is not difficult to calculate
as it appears for a unique term in the expansion of in terms of linear combination of products of the
If
is a reduced word for then
by [Bou, Prop. ????]. Thus
(Straightening for the Let
such that
Then
Proof.
The bar involution on the affine Hecke algebra is the involution
given by
Define by
Let be the longest element of Let
and let
Proof.
The length function on can be given by
Thus, if then
Let and write with
Then, since
and
(b) Since
and
it follows that
The proof for is similar.
(c) Since is
and the coefficients are bar invariant, is an element of
and part (a) implies that
(d) By (a), (b) and ???,
If let be the element of
of maximal length in the double coset
Then
Proof.
The first equality follows from ??? and the identity
Let Let
and let
and
be the maximal length elements in and respectively. Let
(resp.
be the minimal (resp. maximal) length element in the double coset
where the powers of inside the sum are all nonpositive. Thus
By ???,
is a polynomial in and
For all
where denotes the Kazhdan-Lusztig
polynomial for the affine Weyl group
Fock space from Hecke algebras
If let be the stabilizer of
and let be the set of minimal length coset
representatives of cosets of Define
and, for each let
The elements
form a basis of the
Define a
in
by
and define by
The parabolic Kazhdan-Lusztig polynomials are given by
where and
Proof.
Fix and define the
by
Let
Define
where, for
(Straightening for
Assume
Then
(a)
If then
(b)
If then
(c)
In general
Proof.
If then
is a basis of
Proof.
Using ???
For define by
where is the parabolic Kazhdan-Lusztig poylnomial.
Proof.
(Steinberg’s tensor product theorem) Let Then
with
Proof.
Let be the quantum group at the value
For each let
be the Weyl module of highest weight and let
be the simple module of highest weight
(Lusztig conjecture) Let be a primitive
root of unity. Define a vector space isomorphism
Proof.
Crystals
Let
be a Cartan matrix. Define free abelian groups
given by
A crystal is a set with maps
such that
(1)
If then
and if the
(2)
and
(3)
If then
The crystal graph of is the graph with
The space of a crystal is the set
The character of is the weight generating function of
A normal crystal is a crystal such that
If is a normal crystal and the
of is the set
and (3) is equivalent to
so that everystring in a normal crystalis a model for a finite dimensional
If is a normal crystal define a bijection by
The map flips each in
The equality
implies
[Kashiwara, Duke 73 (1994), 383-413] Let be a normal crystal. The maps
define an action of on
Proof.
Let and be crystals. A morphism
is a map
such that
and
A strict morphism is a morphism that commutes with all and all
The tensor product of and is the crystal
If are crystals, then the map
is a crystal isomorphism and so we may simply write
for the tensor product of and
If and are normal crystals then
is normal.
Proof.
If is a crystal the dual crystal is the crystal
with
The crystal graph of is obtained by reversing all the arrows in the crystal graph of
Irreducible crystals
A normal crystal is irreducible if the crystal graph of has a single connected component???
A highest weight path is an element such that
for all
The irreducible highest weight crystals are indexed by
Proof.
We would like to show that there is a unique normal crystal of highest weight
Define
Thus, by definition there is a canonical injection
Let The crystal
is well defined, i.e
Proof.
This reduces the problem of finding to the fundamental weights.
Let Then
exists.
Another characterization?
For each and each
there unique injective maps
such that
The crystal
Define projections
by the composition
The projective system defined by the
allows us to define
for all
For each define a crystal
with
and
(a)
For each there is a crystal injection
(b)
Let
be a sequence of elements of such that each appears an infinite number of times. Then
the subcrystal of
given by
the subcrystal of
generated by
If
is a sequence of elements of such that each appears an infinite number of times the
composition
realize
For each define a crystal
with
for all Then
Define
to be the unique involution such that
THIS DEFINITION NEEDS REWORKING!
Representation crystals
The quantum group is the algebra given by generators
with relations
where
and
(Drinfel’d) The algebra is the unique Cartan
preserving Hopf algebra deformation of
Proof.
An integrable is a
such that
and for each and
and
for
There is a bijection
Proof.
Let be a integrable The
crystal operators and
are the linear operators
determined by
for all and
such that and
The convention is that
A crystal basis of is a pair
for all and such that is stable under
and
and the images of the operators and
on with the definitions
make into a crystal.
For each let
be the irreducible of highest weight
and fix a highest weight vector in
Define homomorphisms of
Define
(a)
Let and let
be the irreducible module of highest weight
Then
is a crystal basis of
(b)
There is a unique crystal basis
of such that, for all
where
is the map induced by
Quiver crystals
Let
be the directed graph with vertex set and an edge
if
Fix an orientiation of i.e. a map
Recall that
Fix
For each
There is a natural
action on the variety
Write
Use the orientation to define a symplectic form on
by
The corresponding moment map
A point
is stable if every
vector space
is Let
If define
for a generic point in Let
and define
Passing to of stable points these maps induce
where
The result is a bijection
Let The set
defined by ??? is a realization of the highest weight crystal of weight
Proof.
Let be a quiver, let
be the opposite orientation and let
For each
such that Let
Define a moment map by
and let
Let
For define
where is any generic point of
Let
and let
be the set of triples
such that
is an exact sequence of vector spaces such that
is For each
let
be the induced maps,
The maps
induce an isomorphism
These maps determine maps on
This is a realization of the crystal
Proof.
Path crystals
Let be the set of paths in
where a path in is the image of a piecewise linear map
Define functions
by
where
and
are the monotone functions given by
To visualize these operations note that
For a path “traveling back and forth with respect to
place a hyperplane parallel to
and through the most negative point of Draw another parallel hyperplane
one unit in the positive direction from
(i.e.
for
Water poured down the tube created by and
will create a waterfall and wet those parts of
corresponding to where the function is increasing.
The new path is the path which follows the same trajectory as
except that the “wet parts” are “reflected with respect to the direction”. In the case,
figure 2, where the “the water flows in the positive direction” then
The set is a normal crystal.
Proof.
Define the concatenation or tensor product of paths and
to be the path given by
The reverse of the path is the path given by
For the
of is the path
given by
Let be the dominant chamber, let be the half-sum of the positive roots and set
Write if
for all
The definitions imply that
Let be a subcrystal of such that
is finite for all Then
where denotes the Weyl character corresponding to
Proof.
Let Then
Let and be such that
Let be maximal such that there is an with
If does not exist then and
If does exist set
Then
and the pairs and
cancel in the sum (???).
Let and let
be a highest weight path with
For example, might be the path given by
Define
so that is the collection of paths obtained by applying finite sequences of
to
Let
(a)
(b)
(c)
(d)
If are defined by
then
Proof.
Let The crystal
This is a crystal for the parabolic subsystem
Let and let
be the irreducible highest weight crystal of highest weight
Proof.
Let and let
Then
Proof.
For paths define
The operators
are the unique operators such that
(1)
(2)
The operators
define an action of on
(3)
and
(4)
If then
and
If then
and
(5)
If and
then
(6)
There is a constant depending only on
such that
If and
then
and
If and
then
Proof.
The crystal
Let
and let be the straightline path from to
Then
is the set of length paths in where each step is a unit step in one of the directions
To compute the operators and
on a path
in place the value
Ignoring read this sequence of from left to right and
succesively remove adjacent pairs until the sequence is of the form
The in this sequence are the normal nodes and the
are the conormal nodes. The good node is the leftmost normal node and the cogood node is the right most conormal node. The good node is
exactly at the position where the path is at its most negative point with respect to the hyperplane
Then
For example, if and and
then the parentheses in the table
indicate the
pairings and the numbers in the top row indicate the resulting sequence of and
Then
The highest weight paths in are the
such that for every and every
the
The map
is given by making the standard tableau
For example, if then
and the map is given by
Let
For a highest weight path
and so the character of the crystal is
Multisegments
Let
The elements of index the (isomorphism classes) of simple representations of the quiver.
A segment is a row of boxes on graph paper with diagonals indexed by
to denote a row of boxes of length such that the leftmost box has content and the rightmost box has content
The set of segments is
The elements of index the (isomorphism classes) of indecomposable (nilpotent) representations of the quiver. A
multisegment is a collection of segment, i.e. an element of
A multisegment is aperiodic if it does not contain
Pictorially, a multisegment is aperiodic if it does not contain a box of height Let
In types and
The elements of index the isomorphism classes of nilpotent representations of the quiver.
The partial order
Consider graph paper with diagonal indexed by A segment is a row
of boxes. A multisegment is a collection of rows of boxes.
Alternatively a multisegment can be viewed as a function
The set of segments is ordered by inclusion.
Define
Then
and so the multisegment can be specified by the numbers
Note that
Define a partial order on multisegments by
If
are segments define a degeneration
by
The degeneration
is elementary if
Pictorially a degeneration takes
and
or, equivalently,
Let be the quiver with
Fix an vector space
The map
provides a bijection
Let and be multisegments and let and
be the corresponding orbits in
Then the following are equivalent
(1)
(2)
(3)
for some sequence of elementary degenerations
Proof.
(1) (2):
and so
(2) (3): If then
(3) (1): Assume
for all segments Find a sequence
of
elementary degenerations which takes to i.e.
The crystal graph
Let
be a multisegment and assume that it is ordered so that
(a)
(b)
if
These conditions are equivalent to saying that
The
is integrally dominant,
where is integrally dominant and
is longest in its coset
Place
above each
above each
above each
Then, ignoring read the sequence of
left to right and successively cancel adjacent
pairs to get a sequence of the form
The in this sequence are the normal nodes and the
are the conormal nodes. The good node is the leftmost normal node and the
cogood node is the right most conormal node.
Define
for each
Remark. If this algorithm is being executed where then take
when
and
mod and
when
and
mod
(a)
In type
is the connected component of
in the crystal graph
(b)
is the crystal graph of
The crystals
Type Let
and identify with the partition which has boxes in row
Let
and define an imbedding
where the entries
are the entries of read in Arabic reading order.
The tensor product representation
The simple
of highest weight is given by
with
Then
If
place
Then the on
is given by
where the first sum is over all which are obtained from by changing a
to and the second sum is over all
which are obtained from by changing a
to
The Fock space
Let for
Define
Define an action of
on by
(a)
These formulas make into a
(b)
If
so that the multisegments form a
basis of then
Proof.
The permutations of the sequence
are indexed by the elements of
where is the number of nodes after pairing.
The group acts on the
pairs by changing a pair
to
For each
define
Then
The first statement is clear. To obtain the second statement
The Hall algebra
A quiver
is a directed graph with vertex set and edge set
with no loops. A nilpotent representation of the quiver
is a pair consisting of an
vector space over
which is nilpotent as an element of The
dimension of is the vector
in
A morphism is a map
for all edges
An extension
is an exact sequence
of morphisms of representations.
The following proposition shows that the constants
and
depend only on the dimension vectors of and
Let and be representations of
with dimension vectors and respectively.
(a)
(b)
(c)
for all
(d)
Proof.
The Ringel-Hall algebra is the vector space with basis
with multiplication given by
where
The type A case
The indecomposable representations
of are identified with segments.
By the analogue of the Krull-Schmidt theorem for representations of quivers every representation is isomorphic to a direct sum of indecomposable representations and so
the isomorphism classes of representations of
are identified with multisegments. Let denote the isomorphism class of the representation
and let
Then
Let and be representations of
with dimension vectors and respectively.
(a)
(b)
(c)
Proof.
(a) Since is linear in and linear in
it is sufficient to check that the formula is correct on indecomposable modules. This follows directly from parts (b) and (c).
(b) Let
be a basis of such that
and let
be a basis of such that
Any homomorphism
must have being a submodule of and
being a submodule of and so the only elements of
are multiples of the map
given by
(a)
(b)
Proof.
(a) Count submodules of type in such that the quotient is of type
These are spaces
in
which are not completely contained in
i.e. satisfies
(a)
(b)
(c)
(d)
The number of such subspaces is
(b) Count submodules of of type such that the quotient is of type
Choosing such a submodule amounts to choosing a codimension space in the graded part of
which is not completely contained in
The number of such subspaces is
For each multisegment
Let be the class of the representation indexed by the multisegment
where the first sum is over all multisegments which are obtained from by adding a box
of content to the end of a row of and the second sum is over all multisegments
obtained from by adding a box of content
to the beginning of a row of
Proof.
(a) Let
Then
Since
and
Thus the coefficient of in is
(b) Let Then
Since and
Thus the coefficient of in
is
For each vertex let
be the class of the representation given by
and, for each edge in
let be the representation given by
Let be a type
quiver with the canonical orientiation. Then
in the Hall algebra.
Proof.
Using Proposition ??? we get
and
The result follows. The calculation for the other case is similar.
Notes and References
[Am1] Y. Amit, Convergence properties of the Gibbs sampler for perturbations of Gaussians, Ann. Statistics 24 (1995), 122–140.
[CG] N. Chriss and V. Ginzburg, Representation Theory and Complex Geometry, Birkhäuser, 1997.
[KKM] S.-J. Kang, M. Kashiwara, and K. Misra, ?? Composition Math. 92 no. 3 (1994), 299-325.
S.-J. Kang, M. Kashiwara, K. Misra, T. Miwa, Nakyashiki, Nakashima, ?? Int. J. Mod. Phys. A 7 Suppl. 1A (1992), 449-484, Proc. RIMS Proj. 1991 Infinite Analysis.
[KS] M. Kashiwara, ?? Duke Math. J. 73 no. ? (1994), 383-413.
[KS] M. Kashiwara and Y. Saito ?? Duke Math. J. 89 no. 1 (1997), ???–???.
Notes and references
This is a typed exert of Representation theory Lecture notes: Chapter 6 by Arun Ram. Research supported in part by National Science Foundation grant DMS-9622985.